To prepare one gallon of a 2% solution using a 20 index fluid, how much arterial fluid is required?

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Multiple Choice

To prepare one gallon of a 2% solution using a 20 index fluid, how much arterial fluid is required?

Explanation:
To determine how much arterial fluid is required to prepare one gallon of a 2% solution using a 20 index fluid, it is important to understand the concept of dilution and the relationship between the index of a solution and the desired percentage of the final solution. When creating a diluted solution, the formula used is: C1 × V1 = C2 × V2 Where: - C1 is the concentration of the original solution, - V1 is the volume of the original solution needed, - C2 is the desired concentration of the final solution, - V2 is the volume of the final solution. In this scenario: - C1, the concentration of the 20 index fluid, can be understood as 20, - C2 is the desired concentration of 2%, which is 0.02 in decimal form, - V2 is one gallon, which equals 128 fluid ounces. To find V1, rearranged, the formula becomes: V1 = (C2 × V2) / C1 Substituting in the values: V1 = (0.02 × 128) / 20 V1 = (2.56) / 20 V1 = 0.128 gallons

To determine how much arterial fluid is required to prepare one gallon of a 2% solution using a 20 index fluid, it is important to understand the concept of dilution and the relationship between the index of a solution and the desired percentage of the final solution.

When creating a diluted solution, the formula used is:

C1 × V1 = C2 × V2

Where:

  • C1 is the concentration of the original solution,

  • V1 is the volume of the original solution needed,

  • C2 is the desired concentration of the final solution,

  • V2 is the volume of the final solution.

In this scenario:

  • C1, the concentration of the 20 index fluid, can be understood as 20,

  • C2 is the desired concentration of 2%, which is 0.02 in decimal form,

  • V2 is one gallon, which equals 128 fluid ounces.

To find V1, rearranged, the formula becomes:

V1 = (C2 × V2) / C1

Substituting in the values:

V1 = (0.02 × 128) / 20

V1 = (2.56) / 20

V1 = 0.128 gallons

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